JEE Advanced Practice Set 4
Original pattern-based JEE Advanced full-length mock with 36 questions: 12 Mathematics, 12 Physics, and 12 Chemistry for practical two-paper strategy practice.
Exam Pattern & Rules
Negative Marking: May apply for some questions
Note: Both papers are compulsory. Pattern is not fixed in the same way as JEE Main.
Practice Set Details
JEE Advanced Practice Set 4: all 36 questions with answers
Try each question first, then open “Show answer” to check the correct option and explanation.
Q1.Solve for x: 3x + 11 = 35.
- A.9
- B.7
- C.10
- D.8
Show answer
Correct answer: D. 8
Subtract 11 from both sides: 3x = 24. Divide by 3: x = 8.
Q2.One root of x² − 22x + 120 = 0 is 10. The other root is:
- A.11
- B.22
- C.12
- D.13
Show answer
Correct answer: C. 12
Product of roots = 120. Other root = 120 ÷ 10 = 12.
Q3.The 8th term of an AP with first term 7 and common difference 3 is:
- A.36
- B.28
- C.25
- D.31
Show answer
Correct answer: B. 28
aₙ = a + (n−1)d = 7 + 7×3 = 28.
Q4.Slope of the line through (4, 3) and (7, 30) is:
- A.9
- B.10
- C.8
- D.11
Show answer
Correct answer: A. 9
Slope = (30−3) ÷ (7−4) = 27 ÷ 3 = 9.
Q5.Value of sin 150° is:
- A.−1/2
- B.√3/2
- C.0
- D.1/2
Show answer
Correct answer: D. 1/2
sin 150° = sin 30° = 1/2.
Q6.A bag contains 10 red and 11 blue balls. Probability of drawing a red ball is:
- A.10/20
- B.12/22
- C.10/21
- D.11/22
Show answer
Correct answer: C. 10/21
P(red) = 10/21.
Q7.Determinant of matrix [[3, 1], [5, 10]] is:
- A.23
- B.25
- C.30
- D.22
Show answer
Correct answer: B. 25
det = ad − bc = 3×10 − 1×5 = 25.
Q8.Evaluate: log₂ₐₑₒₓ10(10^3) [log base 10].
- A.3
- B.4
- C.2
- D.30
Show answer
Correct answer: A. 3
logₐ(a^n) = n, so log_10(10^3) = 3.
Q9.Find 13P2.
- A.78
- B.160
- C.152
- D.156
Show answer
Correct answer: D. 156
13P2 = 13!/(13−2)! = 13×12 = 156.
Q10.Find 13C2.
- A.81
- B.75
- C.78
- D.26
Show answer
Correct answer: C. 78
nC2 = n(n−1)/2 = 13×12/2 = 78.
Q11.Simple interest on Rs 3500 at 10% p.a. for 5 years is:
- A.Rs 3500
- B.Rs 1750
- C.Rs 2250
- D.Rs 1500
Show answer
Correct answer: B. Rs 1750
SI = P×R×T/100 = 3500×10×5/100 = Rs 1750.
Q12.Area of a triangle with base 11 cm and height 10 cm is:
- A.55 cm²
- B.110 cm²
- C.61 cm²
- D.49 cm²
Show answer
Correct answer: A. 55 cm²
Area = (1/2) × base × height = (1/2) × 11 × 10 = 55 cm².
Q13.A body starts with velocity 9 m/s and has acceleration 3 m/s². Its velocity after 3 s is:
- A.15 m/s
- B.21 m/s
- C.12 m/s
- D.18 m/s
Show answer
Correct answer: D. 18 m/s
v = u + at = 9 + 3×3 = 18 m/s.
Q14.For u = 4 m/s, a = 2 m/s², t = 7 s, displacement is:
- A.91 m
- B.75 m
- C.77 m
- D.28 m
Show answer
Correct answer: C. 77 m
s = ut + ½At² = 4×7 + 0.5×2×7² = 77 m.
Q15.Net force needed to give 9 kg mass an acceleration of 4 m/s² is:
- A.13 N
- B.36 N
- C.40 N
- D.32 N
Show answer
Correct answer: B. 36 N
F = ma = 9×4 = 36 N.
Q16.Work done when force 25 N moves a body 10 m in its direction is:
- A.250 J
- B.275 J
- C.225 J
- D.35 J
Show answer
Correct answer: A. 250 J
W = F×d = 25×10 = 250 J.
Q17.A body does 850 J of work in 8 s. Its power is:
- A.212.5 W
- B.114.25 W
- C.101.25 W
- D.106.25 W
Show answer
Correct answer: D. 106.25 W
P = W/t = 850/8 = 106.25 W.
Q18.A body of mass 10 kg moves at 10 m/s. Its momentum is:
- A.90 kg·m/s
- B.20 kg·m/s
- C.100 kg·m/s
- D.110 kg·m/s
Show answer
Correct answer: C. 100 kg·m/s
p = mv = 10×10 = 100 kg·m/s.
Q19.Kinetic energy of 3 kg body moving at 11 m/s is:
- A.178.5 J
- B.181.5 J
- C.33 J
- D.214.5 J
Show answer
Correct answer: B. 181.5 J
KE = ½mv² = 0.5×3×11² = 181.5 J.
Q20.Voltage across a 9 Ω resistor carrying 9 A current is:
- A.81 V
- B.90 V
- C.71 V
- D.20 V
Show answer
Correct answer: A. 81 V
V = IR = 9×9 = 81 V.
Q21.Two resistors 11 Ω and 12 Ω connected in series. Total resistance is:
- A.132 Ω
- B.1 Ω
- C.25 Ω
- D.23 Ω
Show answer
Correct answer: D. 23 Ω
Series: R = R₁ + R₂ = 11 + 12 = 23 Ω.
Q22.Power of a lens with focal length 90 cm is:
- A.2.11 D
- B.0.9 D
- C.1.11 D
- D.90 D
Show answer
Correct answer: C. 1.11 D
P = 1/f = 1/0.9 m = 1.11 D.
Q23.Wave speed for frequency 150 Hz and wavelength 3 m is:
- A.153 m/s
- B.450 m/s
- C.600 m/s
- D.420 m/s
Show answer
Correct answer: B. 450 m/s
v = fλ = 150×3 = 450 m/s.
Q24.Standard acceleration due to gravity at Earth's surface is:
- A.9.8 m/s²
- B.6.7 m/s²
- C.11.2 m/s²
- D.3.7 m/s²
Show answer
Correct answer: A. 9.8 m/s²
g ≈ 9.8 m/s² at Earth's surface.
Q25.If [H⁺] = 10⁻3 mol/L, the pH of the solution is:
- A.4
- B.11
- C.2
- D.3
Show answer
Correct answer: D. 3
pH = −log[H⁺] = −log(10⁻3) = 3.
Q26.Molar mass of CaCl₂ is:
- A.95 g/mol
- B.113 g/mol
- C.111 g/mol
- D.75 g/mol
Show answer
Correct answer: C. 111 g/mol
Add atomic masses: molar mass of CaCl₂ = 111 g/mol.
Q27.Oxidation state of sulfur in Na₂S is:
- A.+6
- B.−2
- C.+2
- D.0
Show answer
Correct answer: B. −2
Na=+1 each, so S=−2.
Q28.Formula of lithium oxide is:
- A.Li₂O
- B.LiO
- C.Li₃O₂
- D.LiO₂
Show answer
Correct answer: A. Li₂O
Li(+1) and O(−2): Li₂O.
Q29.Product when P₂O₅ reacts with water is:
- A.H₃PO₃
- B.HPO₃
- C.H₄P₂O₇
- D.H₃PO₄
Show answer
Correct answer: D. H₃PO₄
P₂O₅ + 3H₂O → 2H₃PO₄.
Q30.Which salt hydrolyses to give acidic solution?
- A.Na₂CO₃
- B.CH₃COONa
- C.NH₄Cl
- D.NaCl
Show answer
Correct answer: C. NH₄Cl
NH₄⁺ hydrolyses: NH₄⁺+H₂O ⇌ NH₃+H₃O⁺.
Q31.Tollens’ reagent (silver mirror test) is given by:
- A.esters
- B.aldehydes
- C.ketones
- D.alcohols
Show answer
Correct answer: B. aldehydes
Aldehydes reduce [Ag(NH₃)₂]⁺ to silver mirror.
Q32.Which metal is liquid at room temperature?
- A.Mercury
- B.Tin
- C.Lead
- D.Bismuth
Show answer
Correct answer: A. Mercury
Mercury (Hg) is liquid at room temperature.
Q33.Number of moles in 18 g of H₂O (M = 18 g/mol) is:
- A.2
- B.3
- C.2.5
- D.1
Show answer
Correct answer: D. 1
n = mass/M = 18/18 = 1 mol.
Q34.De Broglie wavelength is:
- A.h·mv
- B.m/hv
- C.h/mv
- D.mv/h
Show answer
Correct answer: C. h/mv
λ = h/p = h/(mv).
Q35.Bond angle in methane (CH₄) is:
- A.180°
- B.109.5°
- C.90°
- D.120°
Show answer
Correct answer: B. 109.5°
Tetrahedral CH₄: 109.5°.
Q36.Hypo (sodium thiosulfate) is used in photography to:
- A.fix the image (remove unexposed AgBr)
- B.develop the image
- C.wash the film
- D.sensitise the film
Show answer
Correct answer: A. fix the image (remove unexposed AgBr)
Na₂S₂O₃ dissolves unreacted AgBr (fixing).